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Suppose we have an array of non-negative integers called nums, the degree of this array is actually the maximum frequency of any one of its elements. We have to find the smallest possible length of a contiguous subarray of nums, that has the same degree as nums.So, if the input is like [1, 2, 2, 3, 1], then the output will be 2, this is because the input array has a degree of 2 because both elements 1 and 2 appear twice. The subarrays that have the same degree − [1, 2, 2, 3, 1], [1, 2, 2, 3], [2, ... Read More
Suppose we have a string s, we have to find the count of contiguous substrings that have the same number of 0's and 1's, and all the 0's and all the 1's in these substrings are grouped consecutively. If substrings occur multiple times are counted the number of times they occur.So, if the input is like "11001100", then the output will be 6, as the substrings are "1100", "10", "0011", "01", "1100", "10".To solve this, we will follow these steps −Define an array cnt of size 2 and fill this with 0res := 0for initialize i := 0, when i ... Read More
The Comb Sort in Java eliminates the smaller values situated to the end of the list and the inversions are removed oby by one. Let us see an example −Example Live Demoimport java.util.Arrays; public class Demo{ void comb_sort(int nums[]){ int len_gap = nums.length; float shrink_val = 1.3f; boolean swap = false; while (len_gap > 1 || swap) { if (len_gap > 1) { len_gap = (int)(len_gap / shrink_val); } swap ... Read More
Suppose we have a positive integer, we have to check whether it has alternating bits − so, two adjacent bits will always have different values.So, if the input is like 10, then the output will be True, as binary representation of 10 is 1010.To solve this, we will follow these steps −p := n AND 1if n < 2, then −return truen := n/2while n is non-zero, do −c := n AND 1if c XOR p is same as 0, then −return falsep := cn := n/2return trueLet us see the following implementation to get better understanding −Example Live Demo#include ... Read More
The Counting Sort counts the number of objects having distinct key values. Let us see an example −Note − The below code can be used with negative numbers as well.Example Live Demoimport java.util.*; public class Demo{ static void count_sort(int[] arr){ int max_val = Arrays.stream(arr).max().getAsInt(); int min_val = Arrays.stream(arr).min().getAsInt(); int range = max_val - min_val + 1; int count[] = new int[range]; int result[] = new int[arr.length]; for (int i = 0; i < arr.length; i++){ count[arr[i] - min_val]++; ... Read More
Suppose we have a data structure of employee information, there are employee's unique id, his importance value and his direct subordinates' id. As an example, employee 1 is the leader of employee 2, and employee 2 is the leader of employee 3. And suppose their importance values are 15, 10 and 5, respectively. Then employee 1 has a data structure like [1, 15, [2]], and employee 2 has [2, 10, [3]], and employee 3 has [3, 5, []].So, if we have the employee information of a company, and an employee id, we have to find the total importance value of ... Read More
Suppose we have a baseball game point recorder. We have a list of strings; each string can be one of the 4 following types −Integer (one round's score) − Indicates the number of points we get in this round."+" (one round's score) − Indicates the points we get in this round are the sum of the last two valid round's points."D" (one round's score ) − Indicates the points we get in this round are the doubled data of the last valid round's points."C" (an operation, which isn't a round's score) − Indicates the last valid round's points we get ... Read More
Suppose we have an array of integers; we have to find the length of longest continuous increasing subarray.So, if the input is like [2,4,6,5,8], then the output will be 3. As the longest continuous increasing subsequence is [2,4,6], and its length is 3.To solve this, we will follow these steps −if size of nums
Suppose there is a non-empty special binary tree with some non-negative value, here each node in this tree has exactly two or zero children. If the node has two children, then this node's value is the smaller value among its two children. In other words, we can say that [root.val = minimum of root.left.val, root.right.val]. If we have such binary tree, we have to find the second minimum value in the set made of all the nodes' value in the whole tree. If there is no such element, then return -1 instead.So, if the input is likethen the output will ... Read More
Suppose we have a binary tree we have to make a string consists of parenthesis and integers from a binary tree with the preorder traversing way. A null node will be represented by empty parenthesis pair "()". And we need to omit all the empty parenthesis pairs that don't affect the one-to-one mapping relationship between the string and the original binary tree.So, if the input is likethen the output will be 5(6()(8))(7)To solve this, we will follow these steps −ans := blank stringDefine a function pot(). This will take node, sif is null, thenreturn blank stringif if left or right ... Read More