# Longest Continuous Increasing Subsequence in C++

C++Server Side ProgrammingProgramming

Suppose we have an array of integers; we have to find the length of longest continuous increasing subarray.

So, if the input is like [2,4,6,5,8], then the output will be 3. As the longest continuous increasing subsequence is [2,4,6], and its length is 3.

To solve this, we will follow these steps −

• if size of nums <= 1, then −
• return size of nums
• answer := 1, count := 1
• for initialize i := 0, when i < size of nums, update (increase i by 1), do −
• if nums[i] < nums[i + 1], then −
• (increase count by 1)
• Otherwise
• count := 1

Let us see the following implementation to get better understanding −

## Example

Live Demo

#include <bits/stdc++.h>
using namespace std;
class Solution {
public:
int findLengthOfLCIS(vector<int>& nums) {
if (nums.size() <= 1)
return nums.size();
int answer = 1, count = 1;
for (int i = 0; i < nums.size() - 1; i++) {
if (nums[i] < nums[i + 1]) {
count++;
}
else {
count = 1;
}
}
}
};
main(){
Solution ob;
vector<int> v = {2,4,6,5,8};
cout << (ob.findLengthOfLCIS(v));
}

## Input

{2,4,6,5,8}

## Output

3