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Suppose we are given five integer numbers a, b, c, d, n. We have to find out ((ab)(cd)) mod n. The output value is an integer number.So, if the input is like a = 2, b = 3, c = 2, d = 4, n = 10, then the output will be 6.2^3 = 8 2^4 = 16 8^16 = 281474976710656 281474976710656 mod 10 = 6To solve this, we will follow these steps −Define a function helper() . This will take np := ni := 2while i * i 1, thenp := p - floor value of (p / ... Read More
To check whether the interval is closed on the left-side, right-side, both or neither, use the interval.closed property.At first, import the required libraries −import pandas as pdClosed interval set using the "closed" parameter with value "both". A closed interval (in mathematics denoted by square brackets) contains its endpoints, # i.e. the closed interval [0, 5] is characterized by the conditions 0
Suppose we are given a string and an integer k. The string is repeated k times and made to another string. Our task is to find the length of the substring in the new string where 2 * (number of zeroes in substring) 0: continue else: a = min(k - 1, -tmp // list_a[str_len]) v = a * list_a[str_len] - list_a[i] b = bisect_left(list_b, (-v + 1, 0)) - 1 res = max(res, temp_list[b] - i + a * str_len) return res print(solve(2, '0101011'))Input2, '0101011'Output14
To create a half-closed time interval, use the pandas.Interval() and set the closed parameter to right. To check for existence of endpoints, use the in property.At first, import the required libraries −import pandas as pdHalf-Closed interval set using the "closed" parameter with value "right". Half-Closed i.e. (0, 5] is described by 0 < x
Suppose we are given two integer numbers p and q. We have to find out the value of 22^p mod q. The output has to be an integer.So, if the input is like p = 5, q = 6, then the output will be 4To solve this, we will follow these steps −res := 2^(2^p) mod qreturn resExampleLet us see the following implementation to get better understanding −def solve(p, q): res = pow(2, 2 ** p, q) return res print(solve(5, 6))Input5, 6Output4
Suppose we are given a range of integer numbers and are asked to find out the special numbers in the range. A special number is a number that is a positive integer having only 1 digit in its decimal representation. A number that has more than 1 digit in its decimal representation can also be special if the number is divisible by the count of digits in its decimal representation and the quotient value is itself a special number. We return the count of special numbers in the given range (left_limit, right_limit).So, if the input is like left_limit = 5, ... Read More
To create a half-open time interval, use the pandas.Interval() and set the closed parameter to left. To check for existence of endpoints, use the in property.At first, import the required libraries −import pandas as pdHalf-Open interval set using the "closed" parameter with value "left". Half-open i.e. [0, 5) is described by 0
Suppose we are given a matrix that contains n rows and m columns. We have to find out the largest number of consecutive elements in the matrix where the gcd of the elements is greater than 1. The consecutive elements can either lie horizontally or vertically in the matrix.So, if the input is like37912594678510and m = 4, n = 3; then the output will be 3.The fourth column of the given matrix is 12, 6, 10. The gcd of the elements of this column is 2. As there are three elements, the answer is 3.To solve this, we will follow ... Read More
To create an open time interval, use the pandas.Interval() and set the closed parameter to neither. To check for existence of both the endpoints, use the in property.At first, import the required libraries −import pandas as pdOpen interval set using the "closed" parameter with value "neither". An open interval (in mathematics denoted by square brackets) does not contains its endpoints, # i.e. the open interval [0, 5] is characterized by the conditions 0 < x < 5:interval = pd.Interval(left=0, right=20, closed='neither')Display the intervalprint("Interval...", interval)Check for the existence of an element in an Interval. This shows that closed = neither does ... Read More
To create a closed time interval, use the pandas.Interval() and set the closed parameter. To check for existence of both the endpoints, use the in property.At first, import the required libraries −import pandas as pdClosed interval set using the "closed" parameter with value "both". A closed interval (in mathematics denoted by square brackets) contains its endpoints, # i.e. the closed interval [0, 5] is characterized by the conditions 0