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To extract the number of microseconds for each element from TimeDeltaIndex object, use the TimedeltaIndex.microseconds property.At first, import the required libraries −import pandas as pdCreate a TimeDeltaIndex object. We have set the timedelta-like data using the 'data' parameter as well −tdIndex = pd.TimedeltaIndex(data =['10 day 5h 2 min 35s 3us 10ns', '+22:39:19.999999', '2 day 4h 03:08:02.000045', '+21:15:45.999999'])Display TimedeltaIndex −print("TimedeltaIndex...", tdIndex) Display the number of microseconds from each element of TimeDeltaIndex −print("The number of microseconds from the TimeDeltaIndex object...", tdIndex.microseconds)ExampleFollowing is the code −import pandas as pd # Create a TimeDeltaIndex object # We have set the timedelta-like data using ... Read More
To extract the Number of seconds for each element from TimeDeltaIndex object, use the TimedeltaIndex.seconds propertyAt first, import the required libraries −import pandas as pdCreate a TimeDeltaIndex object. We have set the timedelta-like data using the 'data' parameter as well −tdIndex = pd.TimedeltaIndex(data =['10 day 5h 2 min 35s 3us 10ns', '+22:39:19.999999', '2 day 4h 03:08:02.000045', '+21:15:45.999999'])Display TimedeltaIndex −print("TimedeltaIndex...", tdIndex)Display the number of seconds from each element of TimeDeltaIndex −print("The number of seconds from the TimeDeltaIndex object...", tdIndex.seconds)ExampleFollowing is the code −import pandas as pd # Create a TimeDeltaIndex object # We have set the timedelta-like data using the ... Read More
Suppose we have a lowercase string s, we have to find the length of the longest substring that occurs at least twice in s. If we cannot find such string, return 0.So, if the input is like s = "abdgoalputabdtypeabd", then the output will be 3, because the longest substring that occurs more than once is "abd".To solve this, we will follow these steps −Define a function lcs() . This will take s1, s2n := minimum of size of s1 and size of s2for i in range 0 to n - 1, doif s1[i] is not same as s2[i], thenreturn ... Read More
Suppose we have a list of words called w, with lowercase strings. We have to find the length of the longest sequence of w where each previous word is the prefix of the next word and the next word has just one new character appended.So, if the input is like w = ["pqr", "pq", "m", "mn", "pqrs"], then the output will be 3 because we can get the sequence: ["pq", "pqr", "pqrs"], whose length is 3.To solve this, we will follow these steps −sort the list wdp := a map, where default value for a key is 0res := 0for ... Read More
Suppose we have a binary matrix, where 0 indicates empty cell and 1 indicates wall. We can start at any empty cell on first row and want to end up on any empty cell on the last row. We can move left, right, or down, we have to find the longest such path where we can visit each cell at most once. If this is not possible, then return 0.So, if the input is like000000010000then the output will be 10, as We can move (0, 3), (0, 2), (0, 1), (0, 0), (1, 0), (1, 1), (1, 2), (2, 2), ... Read More
Suppose we have a list of numbers called nums, we have to find the maximum length of a contiguous strictly increasing sublist. We are allowed to remove at most single element from the list.So, if the input is like nums = [35, 5, 6, 7, 8, 9, 12, 11, 26], then the output will be 7, because if we remove 12 from nums, the list will be [5, 6, 7, 8, 9, 11, 26], the length is 7, this is the longest, contiguous, strictly increasing sub-list.To solve this, we will follow these steps −if nums is empty, thenreturn 0end := ... Read More
Suppose we have a lowercase string s. This contains English letters as well as "?" Symbol. For each "?" we must either remove it or replace it with any lowercase letter. We have to find the length of the longest consecutively increasing substring that starts with letter "a".So, if the input is like s = "vta???defke", then the output will be 6, as we can turn s into "vtabcdefke" and "abcdef" is the longest consecutively increasing substring, and this is also starting with "a".To solve this, we will follow these steps −maxlen := 0length := 0qmarks := 0for each c ... Read More
Suppose we have a non-negative value n, we have to find the length of the longest consecutive run of 1s in its binary representation.So, if the input is like n = 1469, then the output will be 4, because binary representation of 156 is "10110111101", so there are four consecutive 1sTo solve this, we will follow these steps −count := 0while n is not same as 0, don := n AND (n after shifting one bit to the left)count := count + 1return countExampleLet us see the following implementation to get better understanding −def solve(n): count = 0 while n != 0: n = n & (n
Suppose we have a list of numbers nums and another value diff, we have to find the length of the longest arithmetic subsequence where the difference between any consecutive numbers in the subsequence is same as diff.So, if the input is like nums = [-1, 1, 4, 7, 2, 10] diff = 3, then the output will be 4, because, we can pick the subsequence like [1, 4, 7, 10].To solve this, we will follow these steps −seen := an empty dictionary, default value is 0 when key is not presentmx := 0for each x in nums, doif x - ... Read More
To create a TimeDeltaIndex object, use the pandas.TimedeltaIndex() method.At first, import the required libraries −import pandas as pdCreate a TimeDeltaIndex object. We have set the timedelta-like data using the 'data' parameter as well −tdIndex = pd.TimedeltaIndex(data =['10 day 5h 2 min 3us 10ns', '+22:39:19.999999', '2 day 4h 03:08:02.000045', '+21:15:45.999999'])Display TimedeltaIndex −print("TimedeltaIndex...", tdIndex)Return a dataframe of the components of TimeDeltas −print("The Dataframe of the components of TimeDeltas...", tdIndex.components)ExampleFollowing is the code −import pandas as pd # Create a TimeDeltaIndex object # We have set the timedelta-like data using the 'data' parameter as well tdIndex = pd.TimedeltaIndex(data =['10 day 5h 2 min ... Read More