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Articles on Trending Technologies
Technical articles with clear explanations and examples
Find length of longest subsequence of one string which is substring of another string in C++
Suppose, we have two strings X and Y, and we have to find the length of longest subsequence of string X, which is substring in sequence Y. So if X = “ABCD” and Y = “BACDBDCD”, then output will be 3. As “ACD” is the longest sub-sequence of X, which is substring of Y.Here we will use the dynamic programming approach to solve this problem. So if the length of X is n, and length of Y is m, then create DP array of order (m+1)x(n+1). Value of DP[i, j] is maximum length of subsequence of X[0…j], which is substring ...
Read MoreSort in C++ Standard Template Library (STL)
Here we will see how to use the sort() function of C++ STL to sort an array So if the array is like A = [52, 14, 85, 63, 99, 54, 21], then the output will be [14 21 52 54 63 85 99]. To sort we will use the sort() function, that is present in the header file . The code is like below −Example#include #include using namespace std; int main() { int arr[] = {52, 14, 85, 63, 99, 54, 21}; int n = sizeof(arr) / sizeof(arr[0]); cout
Read MoreFind maximum number of elements such that their absolute difference is less than or equal to 1 in C++
Suppose we have an array of n elements. We have to find the maximum number of elements to select from the array, such that the absolute difference between any two of the chosen elements is less than or equal to 1. So if the array is like [2, 2, 3, 4, 5], then the element will be 3, so the sequence with maximum count is 2, 2, 3.The absolute difference of 0 and 1 means, that the number can be of type x and x + 1. So the idea is to store the frequencies of array elements. So if ...
Read MoreFind maximum number that can be formed using digits of a given number in C++
Suppose we have a number of n digits. We have to find the maximum number that can be obtained using all digits of digits of that number. So if the number is say 339625, then maximum number can be 965332.From the problem, we can see that we can easily sort the digits in non-increasing order, then print them. But we can solve this using more efficient way. We can create one array of size 10 to store the frequency of each digit, then print the numbers from 9 to 0 accordingly.Example#include #include using namespace std; int maxNumFromNum(int num) ...
Read MoreFind a permutation such that number of indices for which gcd(p[i], i) > 1 is exactly K in C++
Suppose we have two integers N and K. We have to find a permutation of integers from the range [1 to N] such that the number of indices (1 – base indexing) where gcd(P[i], i) > 1 is exactly K. So if N = 4 and K = 3, then output will be [1, 2, 3, 4], as gcd(1, 1) = 1, gcd(2, 2) = 2, gcd(3, 3) = 3, gcd(4, 4) = 4If we observe it carefully, we can find that gcd(i, i+1) = 1, gcd(1, i) = 1 and gcd(i, i) = i. As the GCD of any ...
Read MoreFind maximum value of x such that n! % (k^x) = 0 in C++
Suppose we have two integers n and k. We have to find the maximum value of x, such that n! mod (k^x) = 0. So when n = 5, and k = 2, then output will be 3. As n! = 120, now for different values of x, it will be −120 mod 2^0 = 0, 120 mod 2^1 = 0, 120 mod 2^2 = 0, 120 mod 2^3 = 0, 120 mod 2^4 = 8, 120 mod 2^5 = 24, 120 mod 2^6 = 56, 120 mod 2^7 = 120. As the max value of x = 3, the ...
Read MoreFind all combinations of k-bit numbers with n bits set where 1 <= n <= k in sorted order in C++
Suppose we have a number k. Find all possible combinations of k- bit numbers with n set-bits where 1
Read MoreFind minimum cost to buy all books in C++
Suppose we have an array of n elements. These are the ratings of them. Find the minimum cost to buy all books, with the following condition −Cost of each book would be at-least 1 dollarA book has higher cost than an adjacent (left or right) if rating is more than the adjacent.So for example, if the rating array is like [1, 3, 4, 3, 7, 1], Then the output is 10, As 1 + 2 + 3 + 1 + 2 + 1 = 10To solve this, we have to make two arrays called LtoR, and RtoL, and fill them ...
Read MoreFind minimum shift for longest common prefix in C++
Consider we have two strings A and B. The length of A and B are same. In a single shift we can rotate the string B one element. We have to find minimum required shift to get common prefix of maximum length from A and B. So if A = “computerprogramming”, and B = “programminglanguage” So the minimum shift is 8, and prefix is “programming”.Suppose we add the string B at the end of B, so B = B + B, then there is no-need to find prefix of each shift separately. So we have to find the longest prefix ...
Read MoreFind count of Almost Prime numbers from 1 to N in C++
Suppose we have a number N. We have to find almost prime numbers in range 1 to N. A number is called almost prime when it has exactly two distinct factors. The numbers can have any number of non-prime factors, but should be two prime factors. So if N is 2, then output will be 2. There are two numbers 6 and 10.Here we will use the Sieve of Eratosthenes approach. Please check the following implementation to get better idea.Example#include #define N 100005 using namespace std; bool prime[N]; void SieveOfEratosthenes() { for(int i = 0; i
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