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# A freely falling object eventually stops reaching the ground. What happens to its kinetic energy?

__Given:__

It is known that a freely falling object eventually stops reaching the ground.

__To do:__

To find out what happens to the kinetic energy of a freely falling object that eventually stops reaching the ground.

__Solution:__

Let us know about the conversion of energy during the free fall motion of an object from the initial to the final position to get to know what happens to the kinetic energy of a freely falling object that eventually stops reaching the ground.:

__Kinetic energy at initial position:__

When an object is dropped from a certain height for a free fall, its initial velocity is zero.

We know that kinetic energy, $K=\frac{1}{2}mv^2$

Here, $K\rightarrow$ Kinetic energy

$m\rightarrow$ mass

$v\rightarrow$velocity

Therefore, initial at a certain height $h$, the kinetic energy of the object $k=\frac{1}{2}\times m\times 0=0$

The potential energy of the object $P.E=mgh$

__Kinetic energy on reaching the ground:__

On reaching the ground, $v$ is the maximum, and at height, $h=0$

Therefore, the kinetic energy of the object $K=\frac{1}{2}mv^2$

Potential energy, $P.E.=m\times g\times 0=0$

__Energy conversion during the free fall motion__

During the free fall of the object, its potential energy gets decreasing and kinetic energy increases as the velocity of the object increases, and finally, the potential energy of the object gets converted into kinetic energy.

__Conclusion:__

Based on the above discussion we can conclude that when a freely falling object reaches the ground, it eventually stops, and as it touches the hard surface of the ground, the kinetic energy of the object gets converted into heat and sound energy.

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