A man drops a $10\ kg$ rock from the top of a $5\ m$ ladder. What is its kinetic energy when reaches the ground?


Here given, Mass of the rock $m=10\ kg.$

Height of the ladder $h=5\ m$

Gravitational acceleration $g=9.8\ ms^{-2}$

Therefore, Potential energy of the rock $=mgh$

$=10\ kg.\times9.8\ ms^{-2}\times5\ m$

$=490\ Joule$

We know that the potential energy of the rock gets converted into the kinetic energy form.

Therefore kinetic energy of the rock $K=490\ Joule$

Updated on: 10-Oct-2022

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