A child has a die whose six faces show the letters as given below:The die is thrown once. What is the probability of getting (i) A?(ii) D?"

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Given:

A die with faces ($A, B, C, D, E, A$) is thrown once.

To do:

We have to find the probability of getting

(i) $A$.

(ii) $D$

Solution:

When the die is thrown, the total possible outcomes are $A, B, C, D, E, A$

This implies,

The total number of possible outcomes $n=6$.

(i) Number of faces with letter $A=2$

Total number of favourable outcomes $=2$.

We know that,

Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$

Therefore,

Probability of getting $A=\frac{2}{6}$

$=\frac{1}{3}$

The probability of getting $A$ is $\frac{1}{3}$.

(ii) Number of faces with letter $D=1$

Total number of favourable outcomes $=1$.

We know that,

Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$

Therefore,

Probability of getting $D=\frac{1}{6}$

The probability of getting $D$ is $\frac{1}{6}$.

Updated on 10-Oct-2022 13:26:57