A die thrown once.find the probability of getting no. Less than 3

Given: A die is thrown once.

To find: The probability of getting number less than 3.

Solution: Possible outcomes when throwing a die  =  {1 , 2 , 3 , 4 , 5 , 6}

Probability  =  $\frac{Number \ of \ favorable \ outcomes}{Total \  number \ of \ outcomes.}$  

1 , 2 are less than 3 .

So,  Number of favorable outcomes = 2

 Total number of outcomes. = 6

Probability  =  $\frac{2}{6}$                                       [$2 \times3 = 6$]

Probability  =  $\frac{1}{3}$

Therefore the probability of getting number less than 3 is $\frac{1}{3}$