- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- MS Excel
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP
- Physics
- Chemistry
- Biology
- Mathematics
- English
- Economics
- Psychology
- Social Studies
- Fashion Studies
- Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
A die is thrown once. Find the probability of getting
(i) a prime number;
(ii) a number lying between 2 and 6;
(iii) an odd number
Given:
A die is thrown once.
To do:
We have to find the probability of getting
(i) a prime number
(ii) a number lying between 2 and 6
(iii) an odd number
Solution:
When a die is thrown, the total possible outcomes are 1, 2, 3, 4, 5 and 6.
This implies,
The total number of possible outcomes $n=6$.
(i) Prime numbers between 1 and 6 (including 1 and 6) are 2, 3 and 5.
Total number of favourable outcomes $=3$.
We know that,
Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$
Therefore,
Probability of getting a prime number $=\frac{3}{6}$
$=\frac{1}{2}$
The probability of getting a prime number is $\frac{1}{2}$.
(ii) Numbers lying between 2 and 6 are 3, 4 and 5.
Total number of favourable outcomes $=3$.
We know that,
Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$
Therefore,
Probability of getting a number lying between 2 and 6 $=\frac{3}{6}$
$=\frac{1}{2}$
The probability of getting a number lying between 2 and 6 is $\frac{1}{2}$.
(iii) Odd numbers from 1 to 6 are 1, 3 and 5.
Total number of favourable outcomes $=3$.
We know that,
Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$
Therefore,
Probability of getting an odd number $=\frac{3}{6}$
$=\frac{1}{2}$
The probability of getting an odd number is $\frac{1}{2}$.