8085 program to find square of a 8 bit number

In this program, we will see how to find the square of an 8-bit number.

Problem Statement

Write 8085 Assembly language program to find the square of a number The number is stored at location 8000H, store the result at 8050H.

Discussion

In 8085, we cannot perform the multiplication operation directly. We are performing the multiplication by using repetitive addition. To get square of a number, we have to multiply the number with itself.

Input

Address	Data
…	…
8000	0C
…	…

Flow Diagram

Program

Address	HEX Codes	Labels	Mnemonics	Comments
F000	21, 00, 80		LXI H,8000H	Load the number from 8000H
F003	AF		XRA A	Clear accumulator
F004	46		MOV B,M	Load data from memory to B
F005	86	LOOP	ADD M	Add memory byte with A
F006	05		DCR B	Decrease B by 1
F007	C2, 05, F0		JNZ LOOP	If Z = 0, jump to loop
F00A	32, 50, 80		STA 8050H	Store result into memory
F00D	76		HLT	Terminate the program