8085 program to find minimum value of digit in the 8 bit number

MicrocontrollerMicroprocessor8085

In this program we will see how to find the minimum digit from a two-digit number.

Problem Statement

Write 8085 Assembly language program to find the minimum digit from a two-digit number. The number is stored at location 8000H, store the result at 8050H.

Discussion

Here we are performing this task by using masking operation. Each digit takes one nibbles. We are masking the upper nibble by ANDing with 0FH (0000 1111). Store the lower nibble into another register. After that, we are taking the upper nibble. To get it, we are shifting the number to the right four times to convert lower nibble to upper nibble. Now again performing the masking operation the upper nibble is taken. By comparing them we can find the minimum one.

Input

Address
Data


8000
78


Flow Diagram

 

Program

Address
HEX Codes
Labels
Mnemonics
Comments
F000
3A, 00, 80
 
LDA 8000H
Take the number from memory
F003
47
 
MOV B,A
Copy the content of A to B
F004
E6, 0F
 
ANI 0FH
Mask the upper nibble
F006
4F
 
MOV C,A
Store the lower nibble into C
F007
78
 
MOV A,B
Take number from B to A
F008
07
 
RLC
Rotate A content to the left four times
F009
07
 
RLC
 
F00A
07
 
RLC
 
F00B
07
 
RLC
 
F00C
E6, 0F
 
ANI 0FH
Take the lower nibble
F00E
B9
 
CMP C
Compare C with A
F00F
DA, 13, F0
 
JC STORE
If CY = 1, store A to memory
F012
79
 
MOV A,C
Otherwise take C into A
F013
32, 50, 80
STORE
STA 8050H
Store result into memory
F016
76
 
HLT
Terminate the program

Output

Address
Data


8050
07


raja
Published on 11-Mar-2019 12:03:21
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