# 8085 program to find minimum value of digit in the 8 bit number

In this program we will see how to find the minimum digit from a two-digit number.

## Problem Statement

Write 8085 Assembly language program to find the minimum digit from a two-digit number. The number is stored at location 8000H, store the result at 8050H.

## Discussion

Here we are performing this task by using masking operation. Each digit takes one nibbles. We are masking the upper nibble by ANDing with 0FH (0000 1111). Store the lower nibble into another register. After that, we are taking the upper nibble. To get it, we are shifting the number to the right four times to convert lower nibble to upper nibble. Now again performing the masking operation the upper nibble is taken. By comparing them we can find the minimum one.

Data

8000
78

## Program

HEX Codes
Labels
Mnemonics
F000
3A, 00, 80

LDA 8000H
Take the number from memory
F003
47

MOV B,A
Copy the content of A to B
F004
E6, 0F

ANI 0FH
F006
4F

MOV C,A
Store the lower nibble into C
F007
78

MOV A,B
Take number from B to A
F008
07

RLC
Rotate A content to the left four times
F009
07

RLC

F00A
07

RLC

F00B
07

RLC

F00C
E6, 0F

ANI 0FH
Take the lower nibble
F00E
B9

CMP C
Compare C with A
F00F
DA, 13, F0

JC STORE
If CY = 1, store A to memory
F012
79

MOV A,C
Otherwise take C into A
F013
32, 50, 80
STORE
STA 8050H
Store result into memory
F016
76

HLT
Terminate the program

## Output

Data

8050
07

Updated on: 30-Jul-2019

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