8085 Program to Add two 8 Bit numbers

Microprocessor8085

In this program, we will see how to add two 8-bit numbers using 8085 microprocessor.

Problem Statement

Write8085 Assembly language program to add two 8-bit numbers and store the result at locations 8050H and 8051H.

Discussion

To perform this task, we are using the ADD operation of 8085 Microprocessor. When the result of the addition is the 1-byte result, then the carry flag will not be enabled. When the result is exceeding the 1-byte range, then the carry flag will be 1

We are using two numbers at location 8000H and 8001H. When the numbers are 6CH and 24H, then the result will be (6C + 24 = 90) and when the numbers are FCH and 2FH, then the result will be (FC + 2F = 12B) Here the result is exceeding the range of 1-byte.

Input

first input

Address
Data
.
.
.
.
.
.
8000
6C
8001
24
.
.
.
.
.
.

second input

Address
Data
.
.
.
.
.
.
8000
FC
8001
2F
.
.
.
.
.
.

Flow Diagram


Program

Address
HEX Codes
Labels
Mnemonics
Comments
F000
0E,00

MVIC,00H
Clear C register
F002
21,00, 80

LXIH,8000H
Load initial address to get operand
F005
7E

MOVA, M
Load Acc with a memory element
F006
23

INX H
Point to next location
F007
46

MOVB, M
Load B with the second operand
F008
80

SUB B
Add B with A
F009
D2,0D, F0

JNC STORE
When CY = 0, go to STORE
F00C
0C

INR C
Increase C by 1
F00D
21,50, 80
STORE
LXIH,8050H
Load the destination address
F010
77

MOVM, A
Store the result
F011
23

INX H
Point to next location
F012
71

MOVM, C
Store the carry
F013
76

HLT
Terminate the program


Output

first output

Address
Data
.
.
.
.
.
.
8050
90
8051
00
.
.
.
.
.
.

second output

Address
Data
.
.
.
.
.
.
8050
2B
8051
01
.
.
.
.
.
.
raja
Published on 07-Jan-2019 12:42:06
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