Java.lang.StrictMath.log10() Method

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Description

The java.lang.StrictMath.log10() method returns the base 10 logarithm of a double value.It include some cases −

• If the argument is NaN or less than zero, then the result is NaN.
• If the argument is positive infinity, then the result is positive infinity.
• If the argument is positive zero or negative zero, then the result is negative infinity.
• If the argument is equal to 10ⁿ for integer n, then the result is n.

Declaration

Following is the declaration for java.lang.StrictMath.log10() method

public static double log10(double a)

Parameters

a − This is the value.

Return Value

This method returns the base 10 logarithm of a.

Exception

NA

Example

The following example shows the usage of java.lang.StrictMath.log10() method.

package com.tutorialspoint;

import java.lang.*;

public class StrictMathDemo {

   public static void main(String[] args) {

      double d1 = 0.0 , d2 = 1000.0 , d3 = (1.0/0.0), d4 = 1;
   
      // returns natural logarithm (base 10) of a double value.       
      double log10Value = StrictMath.log10(d1); 
      System.out.println("Log " + d1 + " with base 10 = " + log10Value);
        
      // if the argument is equal to 10n for integer n, it returns n.
      log10Value = StrictMath.log10(d2); 
      System.out.println("Log " + d2 + " with base 10 = " + log10Value);

      log10Value = StrictMath.log10(d3); 
      System.out.println("Log " + d3 + " with base 10 = " + log10Value);

      log10Value = StrictMath.log10(d4); 
      System.out.println("Log " + d4 + " with base 10 = " + log10Value);
   }
}

Let us compile and run the above program, this will produce the following result −

Log 0.0 with base 10 = -Infinity
Log 1000.0 with base 10 = 3.0
Log Infinity with base 10 = Infinity
Log 1.0 with base 10 = 0.0