Java.lang.Math.rint() Method

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Description

The java.lang.Math.rint(double a) returns the double value that is closest in value to the argument and is equal to a mathematical integer. If two double values that are mathematical integers are equally close, the result is the integer value that is even. Special cases:

  • If the argument value is already equal to a mathematical integer, then the result is the same as the argument.

  • If the argument is NaN or an infinity or positive zero or negative zero, then the result is the same as the argument.

Declaration

Following is the declaration for java.lang.Math.rint() method

public static double rint(double a)

Parameters

  • a -- a double value.

Return Value

This method returns the closest floating-point value to a that is equal to a mathematical integer.

Exception

  • NA

Example

The following example shows the usage of lang.Math.rint() method.

package com.tutorialspoint;

import java.lang.*;

public class MathDemo {

   public static void main(String[] args) {

      // get two double numbers
      double x = 1654.9874;
      double y = -9765.134;

      // find the closest integers for these double numbers
      System.out.println("Math.rint(" + x + ")=" + Math.rint(x));
      System.out.println("Math.rint(" + y + ")=" + Math.rint(y));

   }
}

Let us compile and run the above program, this will produce the following result:

Math.rint(1654.9874)=1655.0
Math.rint(-9765.134)=-9765.0



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