Java - Math rint(double x) method

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Description

The Java Math rint(double a) returns the double value that is closest in value to the argument and is equal to a mathematical integer. If two double values that are mathematical integers are equally close, the result is the integer value that is even. Special cases −

• If the argument value is already equal to a mathematical integer, then the result is the same as the argument.

• If the argument is NaN or an infinity or positive zero or negative zero, then the result is the same as the argument.

Declaration

Following is the declaration for java.lang.Math.rint() method

public static double rint(double a)

Parameters

a − a double value.

Return Value

This method returns the closest floating-point value to a that is equal to a mathematical integer.

Exception

NA

Example 1

The following example shows the usage of Math rint() method to get a double value for a positive double value.

package com.tutorialspoint;
public class MathDemo {
   public static void main(String[] args) {

      // get a double number
      double x = 1654.9874;

      // find the closest integers for this double number
      System.out.println("Math.rint(" + x + ")=" + Math.rint(x));
   }
}

Output

Let us compile and run the above program, this will produce the following result −

Math.rint(1654.9874)=1655.0

Example 2

The following example shows the usage of Math rint() method to get a double value for a negative double value.

package com.tutorialspoint;
public class MathDemo {
   public static void main(String[] args) {

      // get a double number
      double x = -9765.134;

      // find the closest integers for this double number
      System.out.println("Math.rint(" + x + ")=" + Math.rint(x));
   }
}

Output

Let us compile and run the above program, this will produce the following result −

Math.rint(-9765.134)=-9765.0

Example 3

The following example shows the usage of Math rint() method to get a double value for a zero double values.

package com.tutorialspoint;
public class MathDemo {
   public static void main(String[] args) {

      // get a double number
      double x = -0.0;
      double y = 0.0;	  

      // find the closest integers for these double number
      System.out.println("Math.rint(" + x + ")=" + Math.rint(x));
	  System.out.println("Math.rint(" + y + ")=" + Math.rint(y));
   }
}

Output

Let us compile and run the above program, this will produce the following result −

Math.rint(-0.0)=-0.0
Math.rint(0.0)=0.0