Java.lang.Integer.compareTo() Method

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Description

The java.lang.Integer.compareTo() method compares two Integer objects numerically.

Declaration

Following is the declaration for java.lang.Integer.compareTo() method

public int compareTo(Integer anotherInteger)

Parameters

  • anotherInteger -- This is the Integer to be compared.

Return Value

This method returns the value 0 if this Integer is equal to the argument Integer, a value less than 0 if this Integer is numerically less than the argument Integer and a value greater than 0 if this Integer is numerically greater than the argument Integer.

Exception

  • NA

Example

The following example shows the usage of java.lang.Integer.compareTo() method.

package com.tutorialspoint;

import java.lang.*;

public class IntegerDemo {

   public static void main(String[] args) {

     // compares two Integer objects numerically
     Integer obj1 = new Integer("25");
     Integer obj2 = new Integer("10");
     int retval =  obj1.compareTo(obj2);
    
     if(retval > 0) {
        System.out.println("obj1 is greater than obj2");
     }
     else if(retval < 0) {
        System.out.println("obj1 is less than obj2");
     }
     else {
        System.out.println("obj1 is equal to obj2");
     }
   }
} 

Let us compile and run the above program, this will produce the following result:

obj1 is greater than obj2



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