Java.lang.Double.doubleToRawLongBits() Method

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Description

The java.lang.Double.doubleToRawLongBits() method returns a representation of the specified floating-point value according to the IEEE 754 floating-point "double format" bit layout, preserving Not-a-Number (NaN) values.It includes the following important points:

  • If the argument is positive infinity, the result is 0x7ff0000000000000L.
  • If the argument is negative infinity, the result is 0xfff0000000000000L.
  • If the argument is NaN, the result is the long integer representing the actual NaN value. Different from doubleToLongBits method, doubleToRawLongBits does not collapse all the bit patterns encoding a NaN to a single "canonical" NaN value.

Declaration

Following is the declaration for java.lang.Double.doubleToRawLongBits() method

public static long doubleToRawLongBits(double value)

Parameters

  • value -- This is a double precision floating-point number.

Return Value

This method returns the bits that represent the floating-point number.

Exception

  • NA

Example

The following example shows the usage of java.lang.Double.doubleToRawLongBits() method.

package com.tutorialspoint;

import java.lang.*;

public class DoubleDemo {

   public static void main(String[] args) {

     Double d = new Double("10.50");
   
     //returns the bits that represent the floating-point number
     System.out.println("Value = " + d.doubleToRawLongBits(2.5d));  
   }
} 

Let us compile and run the above program, this will produce the following result:

Value = 4612811918334230528



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