- Trending Categories
- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP

- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who

# Two dice, one blue and one grey, are thrown at the same time.

A student argues that-there are 11 possible outcomes 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 and 12. Therefore, each of them has a probability $\frac{1}{11}$. Do you agree with this argument? Justify your answer.

Given:

Two dice, one blue and one grey, are thrown at the same time.

A student argues that there are 11 possible outcomes 2, 3, 4, 5, 6, 7, 8, 9, 10,11 and 12. Therefore, each of them has a probability $\frac{1}{11}$.

To do:

We have to find whether the argument of the student is correct or false.

Solution:

When two dice (one blue and one green) are thrown at the same time, the total number of outcomes $=6 \times 6=36$

This implies,

The total number of possible outcomes $n=36$.

When the sum on the two dice $=2$, the possible outcome is $(1,1)$

Number of favorable outcomes $=1$

Probability that the sum on the two dice is 2 $=\frac{1}{36}$

When the sum on the two dice $=3$, the possible outcome is $(1,2), (2,1)$

Number of favorable outcomes $=2$

Probability that the sum on the two dice is 3 $=\frac{2}{36}$

When the sum on the two dice $=4$, the possible outcome is $(1,3), (2,2), (3,1)$

Number of favorable outcomes $=3$

Probability that the sum on the two dice is 4 $=\frac{3}{36}$

When the sum on the two dice $=5$, the possible outcome is $(1,4),(2,3),(3,2),(4,1)$

Number of favorable outcomes $=4$

Probability that the sum on the two dice is 5 $=\frac{4}{36}$

When the sum on the two dice $=6$, the possible outcome is $(1,5),(2,4),(3,3),(4,2),(5,1)$

Number of favorable outcomes $=5$

Probability that the sum on the two dice is 6 $=\frac{5}{36}$

When the sum on the two dice $=7$, the possible outcome is $(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)$

Number of favorable outcomes $=6$

Probability that the sum on the two dice is 7 $=\frac{6}{36}$

When the sum on the two dice $=8$, the possible outcome is $(2,6),(3,5),(4,4),(5,3),(6,2)$

Number of favorable outcomes $=5$

Probability that the sum on the two dice is 8 $=\frac{5}{36}$

When the sum on the two dice $=9$, the possible outcome is $(3,6),(4,5),(5,4),(6,3)$

Number of favorable outcomes $=4$

Probability that the sum on the two dice is 9 $=\frac{4}{36}$

When the sum on the two dice $=10$, the possible outcome is $(4,6),(5,5),(6,4)$

Number of favorable outcomes $=3$

Probability that the sum on the two dice is 10 $=\frac{3}{36}$

When the sum on the two dice $=11$, the possible outcome is $(5,6),(6,5)$

Number of favorable outcomes $=2$

Probability that the sum on the two dice is 11 $=\frac{2}{36}$

When the sum on the two dice $=12$, the possible outcome is $(6,6)$

Number of favorable outcomes $=1$

Probability that the sum on the two dice is 12 $=\frac{1}{36}$

No, the outcomes are not equally likely from the above table we see that, there is different probability for different outcomes.

- Related Questions & Answers
- Sum of series 2/3 – 4/5 + 6/7 – 8/9 + …… upto n terms
- Find sum of the series 1-2+3-4+5-6+7....in C++
- Sum of the series 2 + (2+4) + (2+4+6) + (2+4+6+8) + ... + (2+4+6+8+...+2n) in C++
- What are the differences between -std = c++11 and -std = gnu++11?
- How can one believe in science and religion at the same time?
- Find the nth term of the given series 0, 0, 2, 1, 4, 2, 6, 3, 8, 4… in C++
- C++ program to find the sum of the series (1*1) + (2*2) + (3*3) + (4*4) + (5*5) + … + (n*n)
- What are the specifications of one plus 5?
- How To Fix and Protect The Linux Server Against the Dirty COW Vulnerability on CentOS 5/6/7 or RHEL 5/6/7
- Sum of the Series 1/(1*2) + 1/(2*3) + 1/(3*4) + 1/(4*5) + ... in C++
- What are the new changes introduced in C++11?
- Sum of the series 1 + (1+3) + (1+3+5) + (1+3+5+7) + + (1+3+5+7+....+(2n-1)) in C++
- Sum of the series 1 + (1+3) + (1+3+5) + (1+3+5+7) + ...... + (1+3+5+7+...+(2n-1)) in C++
- C++ program to find nth Term of the Series 1 2 2 4 4 4 4 8 8 8 8 8 8 8 8 …
- 3-6-9 in Python
- What are the differences between thunderbolt 2 and thunderbolt 3?