Say true or false and justify your answer:
$(i)$. $10\times10^{11}=100^{11}$
$(ii)$. $2^3$>$5^2$
$(iii)$. $2^3\times3^2=6^5$
$(iv)$. $3^0=(1000)^0$
Given:
$(i)$. $10\times10^{11}=100^{11}$
$(ii)$. $2^3$>$5^2$
$(iii)$. $2^3\times3^2=6^5$
$(iv)$. $3^0=(1000)^0$
To do: To state true or false and justify the answer.
Solution:
$(i)$. $10\times10^{11}=100^{11}$
LHS $=(10^{1+11})$ $a^m\times a^n=a^{m+n}$
$=10^{12}$
RHS $==(10^2)^11$
$= (10)^{2\times11}$
$= 10^{22}$
Thus the above equation is false.
$(ii)$. $2^3>5^2$
Or $2\times2\times2$>$5\times5$
Or $8>25$
But 8<25
Thus the above equation is false.
$(iii)$. $2^3\times3^2=6^5$
Or
LHS $=2\times2\times2\times3\times3$
$=9\times8$
$=72$
RHS $=6\times6\times6\times6\times6\times=7776$
But $LHS≠RHS$
Thus the above equation is false.
$(iv)$. $3^0=(1000)^0$
$1=1$ $[\because a^0=1]$
$LHS=RHS$
Thus the equation is true.
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