Through a rectangular field of length $90\ m$ and breadth $60\ m$, two roads are constructed which are parallel to the sides and cut each other at right angles through the centre of the fields. If the width of each road is $3\ m$, find
$(i)$ the area covered by the roads.
$(ii)$ the cost of constructing the roads at the rate of $₹ 110\ per\ m^2$.

AcademicMathematicsNCERTClass 7

Length of the road along the length of the field$= 90\ m$

Breadth$= 3\ m$

Area of the road$= l\times b$


Similarly, the area of the road parallel to the breadth of the field$=l\times b$

$=60\ m\times3\ m=180\ m^2$

Area of the common portion$=3\ m\times3\ m=9m^2$

$(i)$. Area of the two roads

$=270\ m^2+180\ m^2-9\ m^2$

$=450\ m^2-9\ m^2=441\ m^2$

$(ii)$. Cost of constructing the roads

$=Rs\ 110\times441=Rs\ 48,510$
Updated on 10-Oct-2022 13:36:06