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# A verandah of width $2.25\ m$ is constructed all along outside a room which is $5.5\ m$ long and $4\ m$ wide. Find:

$(i)$ the area of the verandah.

$(ii)$ the cost of cementing the floor of the verandah at the rate of $â‚¹\ 200\ per\ m^2$

Length of the room$= 5.5\ m$

Breadth of the room$= 4\ m$

Area of the room$=l\times b=5.5\ m\times4\ m=22\ m^2$

Width of the verandah$= 2.25\ m$

Length of the room including verandah

$=5.5\ m+2\times2.25\ m=10\ m$

The breadth of the room including verandah

$=4\ m+2\times2.25\ m=8.50\ m^2$

Area of the room including verandah$=l\times b$

$=10\ m\times8.50\ m=85\ m^2$

$(i)$. Area of the verandah$=85\ m^2-22\ m^2=63m^2$

$(ii)$. Cost of cementing the floor of the verandah$=Rs\ 63\times200=Rs\ 12600$

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