A verandah of width $2.25\ m$ is constructed all along outside a room which is $5.5\ m$ long and $4\ m$ wide. Find:
$(i)$ the area of the verandah.
$(ii)$ the cost of cementing the floor of the verandah at the rate of $₹\ 200\ per\ m^2$
Length of the room$= 5.5\ m$
Breadth of the room$= 4\ m$
Area of the room$=l\times b=5.5\ m\times4\ m=22\ m^2$
Width of the verandah$= 2.25\ m$
Length of the room including verandah
$=5.5\ m+2\times2.25\ m=10\ m$
The breadth of the room including verandah
$=4\ m+2\times2.25\ m=8.50\ m^2$
Area of the room including verandah$=l\times b$
$=10\ m\times8.50\ m=85\ m^2$
$(i)$. Area of the verandah$=85\ m^2-22\ m^2=63m^2$
$(ii)$. Cost of cementing the floor of the verandah$=Rs\ 63\times200=Rs\ 12600$
 
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