- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- MS Excel
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP
- Physics
- Chemistry
- Biology
- Mathematics
- English
- Economics
- Psychology
- Social Studies
- Fashion Studies
- Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
The lid of a rectangular box of sides $ 40 \mathrm{~cm} $ by $ 10 \mathrm{~cm} $ is sealed all round with tape. What is the length of the tape required?
Given:
The lid of a rectangular box of sides $40 \mathrm{~cm}$ by $10 \mathrm{~cm}$ is sealed all round with tape.
To do:
We have to find the length of the tape required.
Solution:
We know that,
Perimeter of a rectangle of length $l$ and breadth $b$ is $2(l+b)$
Tape is sealed around the rectangular box.
Length $=40\ cm$ and breadth $=10\ cm$
Therefore,
The perimeter of the given rectangular box $= 2 (l+b)$
$= 2 (40+10)$
$= 2(50)$
$= 100\ cm$
Therefore the length of the required tape is $100\ cm$.
Advertisements
To Continue Learning Please Login
Login with Google