- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- MS Excel
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP
- Physics
- Chemistry
- Biology
- Mathematics
- English
- Economics
- Psychology
- Social Studies
- Fashion Studies
- Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
The angles of a triangle are $ x, y $ and $ 40^{\circ} $. The difference between the two angles $ x $ and $ y $ is $ 30^{\circ} $. Find $ x $ and $ y $.
Given:
The angles of a triangle are \( x, y \) and \( 40^{\circ} \). The difference between the two angles \( x \) and \( y \) is \( 30^{\circ} \).
To do:
We have to find \( x \) and \( y \).
Solution:
We know that,
The sum of the angles of a triangle is $180^o$
Therefore,
$x+y+40^o=180^o$
$x+y=180^o-40^o$
$x+y=140^o$..........(i)
The difference between the two angles \( x \) and \( y \) is \( 30^{\circ} \).
This implies,
$x-y=30^o$........(ii)
Adding (i) and (ii), we get,
$2x=140^o+30^o$
$x=\frac{170^o}{2}$
$x=85^o$
$\Rightarrow y=85^o-30^o$
$y=55^o$
Hence, $x=85^o$ and $y=55^o$.
Advertisements