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Suppose we have a list of distinct words, we have to find the number of different ways we can concatenate two different words from the given list of words to make a palindrome.

So, if the input is like words = ["time", "emit", "mo", "m"], then the output will be 3, as we can make "timeemit", "emittime", and "mom".

To solve this, we will follow these steps −

res := 0

ln := number of words in the array

for k in range 0 to 1, do

for i in range 0 to ln − 1, do

for j in range i + 1 to ln − 1, do

res := res + (1 when words[i] concatenate words[j] is palindrome, otherwise 0)

words := words in reverse order

return res

Let us see the following implementation to get better understanding −

class Solution: def solve(self, words): def is_palindrome(w1, w2): w3 = w1 + w2 return w3 == w3[::−1] res = 0 ln = len(words) for k in range(2): for i in range(ln): for j in range(i + 1, ln): res += is_palindrome(words[i], words[j]) words = words[::−1] return res ob = Solution() words = ["time", "emit", "mo", "m"] print(ob.solve(words))

["time", "emit", "mo", "m"]

3

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