# Program to find number of ways we can get n R.s using Indian denominations in Python

PythonServer Side ProgrammingProgramming

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Suppose we have limited coins of denominations (₹1, ₹2, ₹5 and ₹10). We have to find in how many ways can you sum them up to a total of ₹n? We have an array count of size 4, where count indicates coins of ₹1, count indicates coins of ₹2 and so on.

So, if the input is like n = 25 count = [7,3,2,2], then the output will be 9.

To solve this, we will follow these steps −

• denom := [1,2,5,10]
• A := an array of size (n + 1) and fill with 0
• B := a new list from A
• for i in range 0 to (minimum of count and n), do
• A[i] := 1
• for i in range 1 to 3, do
• for j in range 0 to count[i], do
• for k in range 0 to n + 1 - j *denom[i], do
• B[k + j * denom[i]] := B[k + j * denom[i]] + A[k]
• for j in range 0 to n, do
• A[j] := B[j]
• B[j] := 0
• return A[n]

## Example

Let us see the following implementation to get better understanding −

denom = [1,2,5,10]
def solve(n, count):
A =  * (n + 1)
B = list(A)
for i in range(min(count, n) + 1):
A[i] = 1
for i in range(1, 4):
for j in range(0, count[i] + 1):
for k in range(n + 1 - j *denom[i]):
B[k + j * denom[i]] += A[k]
for j in range(0, n + 1):
A[j] = B[j]
B[j] = 0
return A[n]

n = 25
count = [7,3,2,2]
print(solve(n, count))

## Input

25, [7,3,2,2]


## Output

9