Program to count number of words we can generate from matrix of letters in Python
Suppose we have a 4 x 4 board of letters and a list of words, we have to find the largest number of words that can be generated in the board by a sequence of adjacent letters, using one cell at most once per word (but we can reuse cells for other words). We can go up, down, left, right, or diagonal direction.
So, if the input is like
words = ["bat", "far", "mat"], then the output will be 3, as we can generate mat [0,1] → [1,1] → [2,0], bat [0,2] → [1,1] → [2,2], and far [0,2] → [1,3] → [2,3].
To solve this, we will follow these steps −
N := row count of A, M := column count of size of A
trie := a new map
for each word in words, do
current := trie
for each c in word, do
if c is in current, then
otherwise,
current[c] := a new map
current := current[c]
current["*"] := True
ans := 0
Define a function dfs() . This will take x, y, d
if "*" is in d, then
remove d["*"]
ans := ans + 1
temp := A[x, y]
A[x, y] := "#"
for each item i in [x - 1, x, x + 1], do
A[x, y] := temp
From the main method do the following −
for i in range 0 to N, do
return ans
Example (Python)
Let us see the following implementation to get better understanding −
Live Demo
class Solution:
def solve(self, A, words):
N = len(A)
M = len(A[0])
trie = dict()
for word in words:
current = trie
for c in word:
if c in current:
current = current[c]
else:
current[c] = dict()
current = current[c]
current["*"] = True
ans = 0
def dfs(x, y, d):
nonlocal ans
if "*" in d:
del d["*"]
ans += 1
temp = A[x][y]
A[x][y] = "#"
for i in [x - 1, x, x + 1]:
for j in [y - 1, y, y + 1]:
if 0 <= i < N and 0 <= j < M and A[i][j] in d: dfs(i, j, d[A[i][j]])
A[x][y] = temp
for i in range(N):
for j in range(M):
if A[i][j] in trie:
dfs(i, j, trie[A[i][j]])
return ans
ob = Solution()
matrix = [
["m", "b", "f", "d"],
["x", "a", "y", "a"],
["t", "z", "t", "r"],
["s", "q", "q", "q"]
]
words = ["bat", "far", "mat"]
print(ob.solve(matrix, words))
Input
[
["m", "b", "f", "d"],
["x", "a", "y", "a"],
["t", "z", "t", "r"],
["s", "q", "q", "q"] ],
["bat", "far", "mat"]
Output
3
Published on 21-Dec-2020 18:30:27
