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# Program to find N-th term of series 2, 4, 3, 4, 15… in C++

In this problem, we are given a number N. Our task is to create a program to find N-th term of series 2, 4, 3, 4, 15… in C++.

**Problem Description** − To find the sum of the given series,

**2, 4, 3, 4, 15, 0, 14, 16 .... N terms**

We will find the formula for the general term of the series.

**Let’s take an example to understand the problem,**

**Input** − N = 9

**Output** − 9

## Solution Approach:

The increase of the values in the series is linear i.e. no square values are in the series. Also, it’s value depends on other factors too (division by 2 and 3, as 6 gives 0).

So, we will first take out N (i.e. 1, 2, 3) from their value from the series.

Series: 1*(2), 2*(2), 3*(1), 4*(1), 5*(3), 6*(0), …

On observing this we can deduct the general formula is −

**T _{n} = ( N*((N%2)+(N%3)) )**

## Program to show the implementation of our solution,

#include <iostream> using namespace std; int findNTerm(int N) { int nthTerm = ( N*((N%2) + (N%3)) ); return nthTerm; } int main() { int N = 10; cout<<N<<"th term of the series is "<<findNTerm(N); return 0; }

## Output:

10th term of the series is 10

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