- Trending Categories
- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP

- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who

In this problem, we are given an integer N. The task is to find n-th term in series 1 2 2 3 3 3 4….

**Let’s take an example to understand the problem,**

N = 6

3

The series upto nth term is 1, 2, 2, 3, 3, 3, ...

A simple approach to solve the problem is by using a nested loop. The outer for loop is from 1 to n. And the inner loop is from 1 to i (iterator of outer loop). For each iteration in the inner loop, count the number of elements of the series and return the value of i when count is equal to n.

A more efficient approach to solve the problem is using pattern positions. The elements of the sequence is with their positions in the series are −

Element 1: position 1 Element 2: position 2, 3 Element 3: position 4, 5, 6 Element 4: position 7, 8, 9, 10

For these values, we can create a series using the last position of element in the series which is,

1, 3, 6, 10, 15, 21, 28, ….

x appears in term, 1 + 2 + 3 + … + (x-2) + (x-1)...

This can be generalised as n = x*(x-1)/2

2n = x^{2} - x => x^{2} - x - 2n = 0

Solve the equation using formula for solution of quadratic equation,

$$x=1/2*(1+\sqrt{1+8*n)}$$

**Program to illustrate the working of our solution,**

#include <bits/stdc++.h> using namespace std; int findNthTerm(int n) { int x = (((1) + (double)sqrt(1 + (8 * n))) / 2); return x; } int main(){ int n = 12; cout<<"The series is 1, 2, 2, 3, 3, 3, 4, 4, ...\n"; cout<<n<<"th term of the series is "<<findNthTerm(n); return 0; }

The series is 1, 2, 2, 3, 3, 3, 4, 4, ... 12th term of the series is 5

- Related Questions & Answers
- Sum of the series 1 + (1+2) + (1+2+3) + (1+2+3+4) + ... + (1+2+3+4+...+n) in C++
- Program to find sum of series 1*2*3 + 2*3*4+ 3*4*5 + . . . + n*(n+1)*(n+2) in C++
- Program to find sum of series 1 + 2 + 2 + 3 + 3 + 3 + .. + n in C++
- Sum of the Series 1/(1*2) + 1/(2*3) + 1/(3*4) + 1/(4*5) + ... in C++\n
- Program to find N-th term of series 0, 2,1, 3, 1, 5, 2, 7, 3...in C++
- C++ Program to find the sum of a Series 1/1! + 2/2! + 3/3! + 4/4! + …… n/n!
- C++ program to find the sum of the series 1/1! + 2/2! + 3/3! + 4/4! +…….+ n/n!
- Program to find N-th term of series 2, 4, 3, 4, 15… in C++
- Program to find N-th term of series 0, 0, 2, 1, 4, 2, 6, 3, 8…in C++
- C++ program to find the sum of the series (1*1) + (2*2) + (3*3) + (4*4) + (5*5) + … + (n*n)
- Python Program to find the sum of a Series 1/1! + 2/2! + 3/3! + 4/4! +…….+ n/n!
- Java Program to find the sum of a Series 1/1! + 2/2! + 3/3! + 4/4! +…….+ n/n!
- Sum of the series 1^1 + 2^2 + 3^3 + ... + n^n using recursion in C++
- C++ program to find the sum of the series 1 + 1/2^2 + 1/3^3 + …..+ 1/n^n
- Sum of the series 1 / 1 + (1 + 2) / (1 * 2) + (1 + 2 + 3) / (1 * 2 * 3) + … + upto n terms in C++

Advertisements