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C++ program to find Nth term of series 1, 4, 15, 72, 420…
In this problem, we are given an integer N. Our task is to create a program to Find Nth term of series 1, 4, 15, 72, 420…
Let’s take an example to understand the problem,
Input
N = 4
Output
72
Solution Approach
A simple approach to solve the problem is the formula for the Nth term of the series. For this, we need to observe the series and then generalise the Nth term.
The series can be seen as the product of factorial and a some variables,
1, 4, 15, 72, 420… 1!*(X1), 2!*(X2), 3!*(X3), 4!*(X4), 5!*(X5)... 1*(1), 2*(2), 6*(5/2), 24*(3), 120*(7/2)...
Here, the series of product is,
1, 2, 2.5, 3, 3.5…
It is {(n+2)/2}.So the formula of Nth term is
T(N) = ( N! * (N + 2)/ 2 )
Program to illustrate the working of our solution,
Example
#include <iostream>
using namespace std;
int calcFactorial(int N) {
int factorial = 1;
for (int i = 1; i <= N; i++)
factorial = factorial * i;
return factorial;
}
int calcNthTerm(int N) {
return (calcFactorial(N) * (N + 2) / 2);
}
int main() {
int N = 7;
cout<<N<<"th term of the series is "<<calcNthTerm(N);
return 0;
}Output
7th term of the series is 22680
Updated on: 13-Mar-2021
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