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# Program to find N-th term of series 3, 6, 18, 24, … in C++

In this problem, we are given a number N. Our task is to create a Program to find N-th term of series 3, 6, 18, 24, … in C++.

**Problem Description** − To find the Nth term of the series −

**3, 6, 18, 24, 45, 54, 84 … N Terms**

We need to find the general formula for the given series.

## Let’s take an example to understand the problem,

**Input** − N = 10

**Output** − 150

## Solution Approach:

To find the general term of the series, we will first observe the series and check all the possible generalizations of the series. Like, 3 is common in all but as you go-ahead, you will find that it will not provide any result.

Here, we can also take out the term n i.e. 1, 2, 3. From their values in series to give it a new form. Further checking the remaining value, we will get the following general formula.

## General Term of the series

T_{n}= (n*((n/2) + ((n%2) *2) + 5))

## Example

#include <iostream> using namespace std; int findNTerm(int N) { int nthTerm = ( N*((N/2)+ ((N%2)*2) + N) ); return nthTerm; } int main() { int N = 7; cout<<N<<"th term of the series is "<<findNTerm(N); return 0; }

## Output:

7th term of the series is 84

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