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Program to find N-th term of series 1 4 15 24 45 60 92... in C++
In this problem, we are given a number N. Our task is to create a program to find N-th term of series 1 4 15 24 45 60 92... in C++.
Problem description − To find the nth term of the series −
1, 4, 15, 24, 45, 60, 92, 112 … N terms
We will find the general formula for the series.
Let’s take an example to understand the problem,
Input − N = 6
Output − 60
Solution Approach,
The general term of the series is based on whether the value of N is even or odd. This type of series is a bit complex to recognize but once you think of series as two different for even and odd, it is quite easy to find the general term.
The general term is −
TN = ((2 * (N^2)) - N), if n is odd. TN = (2 * ((N^2) - N)), if n is even.
Program to illustrate the working of our solution,
#include <iostream>
using namespace std;
int findNTerm(int N) {
if (N%2 == 0)
return ( 2*((N*N)-N) );
return ( (2*(N*N)) - N );
}
int main()
{
int N = 10;
cout<<N<<"th term of the series is "<<findNTerm(N);
return 0;
}Output:
10th term of the series is 180
Updated on: 03-Oct-2020
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