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# Program to find N-th term of series 1 4 15 24 45 60 92... in C++

In this problem, we are given a number N. Our task is to create a program to find N-th term of series 1 4 15 24 45 60 92... in C++.

**Problem description** − To find the nth term of the series −

1, 4, 15, 24, 45, 60, 92, 112 … N terms

We will find the general formula for the series.

**Let’s take an example to understand the problem,**

**Input** − N = 6

**Output** − 60

## Solution Approach,

The general term of the series is based on whether the value of N is even or odd. This type of series is a bit complex to recognize but once you think of series as two different for even and odd, it is quite easy to find the general term.

The general term is −

T_{N}= ((2 * (N^2)) - N), if n is odd. T_{N}= (2 * ((N^2) - N)), if n is even.

## Program to illustrate the working of our solution,

#include <iostream> using namespace std; int findNTerm(int N) { if (N%2 == 0) return ( 2*((N*N)-N) ); return ( (2*(N*N)) - N ); } int main() { int N = 10; cout<<N<<"th term of the series is "<<findNTerm(N); return 0; }

## Output:

10th term of the series is 180

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