Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Probability of rain on N+1th day in C++
Given with an array containing 0’s and 1’s where 0’s represents no rain and 1’s represent rainy day. The task is to calculate the probability of rain on N+1th day.
To calculate the probability of rain on N+1th day we can apply the formula
Total number of rainy days in the set / total number of days in a
Input
arr[] = {1, 0, 0, 0, 1 }
Output
probability of rain on n+1th day : 0.4
Explanation
total number of rainy and non-rainy days are: 5 Total number of rainy days represented by 1 are: 2 Probability of rain on N+1th day is: 2 / 5 = 0.4
Input
arr[] = {0, 0, 1, 0}
Output
probability of rain on n+1th day : 0.25
Explanation
total number of rainy and non-rainy days are: 4 Total number of rainy days represented by 1 are: 1 Probability of rain on N+1th day is: 1 / 4 = 0.25
Approach used in the given program is as follows
Input the elements of an array
Input 1 for representing rainy day
Input 0 for representing non-rainy day
Calculate the probability by applying the formula given above
Print the result
Algorithm
Start
Step 1→ Declare Function to find probability of rain on n+1th day
float probab_rain(int arr[], int size)
declare float count = 0, a
Loop For int i = 0 and i < size and i++
IF (arr[i] == 1)
Set count++
End
End
Set a = count / size
return a
step 2→ In main()
Declare int arr[] = {1, 0, 0, 0, 1 }
Declare int size = sizeof(arr) / sizeof(arr[0])
Call probab_rain(arr, size)
Stop
Example
#include <bits/stdc++.h>
using namespace std;
//probability of rain on n+1th day
float probab_rain(int arr[], int size){
float count = 0, a;
for (int i = 0; i < size; i++){
if (arr[i] == 1)
count++;
}
a = count / size;
return a;
}
int main(){
int arr[] = {1, 0, 0, 0, 1 };
int size = sizeof(arr) / sizeof(arr[0]);
cout<<"probability of rain on n+1th day : "<<probab_rain(arr, size);
return 0;
}
Output
If run the above code it will generate the following output −
probability of rain on n+1th day : 0.4
Advertisements