Last updated at May 29, 2018 by Teachoo

Transcript

Example 8 P is a point equidistant from two lines l and m intersecting at point A (see figure). Show that the line AP bisects the angle between them. Given: PB = PC & PBA = PCA = 90 To prove: PAB = PAC Proof In PAB and PAC. PBA = PCA PA = PA PB = PC So, PAB PAC PAB = PAC Hence proved.

Chapter 7 Class 9 Triangles (Term 1)

Serial order wise

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.