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What is the probability of getting atleast one tail, when a pair of coin is tossed once?
Given: A pair of coin is tossed once.
To do: To find the probability of getting atleast one tail.
Solution:
Let's 'H' is the event to be head and 'T' is the event to be a tail.
Possible events when a pair of coin is tossed$=[HH,HT,TH,TT]$
$\therefore$, Total number of possible outcomes$=4$
$\therefore$ events to be a tail $=[HH,HT,TH]$
No. of favorable outcomes$=3$
therefore probability of getting atleast one tail $=\frac{Total\ no.\ of\ favorable\ outcomes}{Total\ no.\ of\ possible\ outcomes}=\frac{3}{4}$
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