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Rahim tosses two different coins simultaneously. Find the probability of getting at least one tail.
Given: Rahim tosses two coins simultaneously.
To do: To find the probability of getting at least one tail.
Solution:
Rahim tosses two coins simultaneously.
The sample space of the experiment is$( HH,\ HT,\ TH,\ and\ TT)$.
Total number of outcomes $=\ 4$
Outcomes in favor of getting at least one tail on tossing the two coins $=\ ( HT,\ TH,\ TT)$
Number of outcomes in favor of getting at least one tail $=\ 3$
Probability of getting at least one tail on tossing the two coins$=\frac{Total\ number\ of\ favorable\ outcomes}{Total\ number\ of\ outcomes}$
$=\frac{3}{4}$
Hence, The probability of getting at least one tail is $\frac{3}{4}$.
Updated on: 10-Oct-2022
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