Water in a canal, 5-4 m wide and 1-8 m deep, is flowing with a speed of 25 km/hour. How much area can it irrigate in 40 minutes, if 10 cm of standing water is required for irrigation ?
Given: Canal width $=\ 5.4\ mt$, Depth$=1.8\ mt$, Water flow speed $=25\ km/hr$, required standing water$=10\ cm$.
To do: To find the irrigated area in 40 minutes.
Solution:
Given canal width$=\ 5.4\ mt$
Depth$=\ 1.8\ mt$
Water flow speed $= 25\ km/hr$
Required irrigation of the water$=10\ cm=10\times 10^{-2}$
Distance covered by water in 40 minutes$=\frac{25\times 40}{60}\ km$
$=\frac{50}{3} \ km$
Volume of water flows through pipe$=\frac{50}{3} \times 5.4\times 1.8\times 1000$
$=162\times 10^{3} \ m^{3}$
Area irrigate with $10\ cm$ of water standing $=\frac{162\times 10^{3}}{10\times 10^{-2}}$
$=162\times 10^{4} \ m^{2}$
Area irrigate with $10\ cm$ of water standing is $162\times 10^{4} \ m^{2}$
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