Water in a canal $1.5\ m$ wide and $6\ m$ deep is flowing with a speed of $10\ km/hr$. How much area will it irrigate in 30 minutes if $ 8 \mathrm{~cm} $ of standing water is desired?

Given:

Water in a canal $1.5\ m$ wide and $6\ m$ deep is flowing with a speed of $10\ km/hr$.

\( 8 \mathrm{~cm} \) of standing water is desired.

To do:

We have to find the area it will irrigate in 30 minutes.

Solution:

Width of the canal $b=1.5 \mathrm{~m}$

Depth of the canal $h=6 \mathrm{~m}$

Speed of the water flow $=10 \mathrm{~km} / \mathrm{hr}$

Flow of water in 30 minutes $l=\frac{10}{2}$

$=5 \mathrm{~km}$

$=5000 \mathrm{~m}$

Therefore,

Volume of water used for irrigation $=l b h$

$=5000 \times 1.5 \times 6$

$=45000 \mathrm{~m}^{3}$

Height of the water in the field $=8 \mathrm{~cm}$

$=\frac{8}{100} \mathrm{~m}$

Area of the field irrigated $=$ Volume of the water $\div$ Height of the water in the field

$=\frac{45000}{\frac{8}{100}}$

$=\frac{45000 \times 100}{8}$

$=5625 \times 100$

$=562500 \mathrm{~m}^{2}$

The area will it irrigate in 30 minutes is $562500\ m^2$.

Tutorialspoint

Simply Easy Learning

Updated on: 10-Oct-2022

57 Views

Kickstart Your Career

Get certified by completing the course

Get Started