Verify$a\ -\ ( -b) \ =\ a\ +\ b$ for the following values of a and b.
(i) a = 21, b = 18
(ii) a = 118, b = 125
(iii) a = 75, b = 84
(iv) a = 28, b = 11
Given:
Some values of a and b.
To verify:
We have to find the value of $a\ -\ ( -b) \ =\ a\ +\ b$
Solution:
(i) a = 21, b = 18
So,
$a\ -\ (-b)\ =\ a\ +\ b$
$21\ -\ (-18)\ =\ 21\ +\ 18$
$21\ +\ 18\ =\ 39$
$\mathbf{39\ =\ 39}$
(ii) a = 118, b = 125
So,
$a\ -\ (-b)\ =\ a\ +\ b$
$118\ -\ (-125)\ =\ 118\ +\ 125$
$118\ +\ 125\ =\ 243$
$\mathbf{243\ =\ 243}$
(iii) a = 75, b = 84
So,
$a\ -\ (-b)\ =\ a\ +\ b$
$75\ -\ (-84)\ =\ 75\ +\ 84$
$75\ +\ 84\ =\ 159$
$\mathbf{159\ =\ 159}$
(iv) a = 28, b = 11
So,
$a\ -\ (-b)\ =\ a\ +\ b$
$28\ -\ (-11)\ =\ 28\ +\ 11$
$28\ +\ 11\ =\ 39$
$\mathbf{39\ =\ 39}$
Hence, we can see that in every case $a\ -\ (-b)\ =\ a\ +\ b$.
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