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If $a=2$ and $b=-2$ find the value of
$(i)$. $a^2+b^2$
$(ii)$. $a^2+ab+b^2$
$(iii)$. $a^{2}-b^2$
Given:
$(i)$. $a^2+b^2$
$(ii)$. $a^2+ab+b^2$
$(iii)$. $a^{2}-b^2$
To do: To find the value of the given expression if $a=2$ and $b=-2$.
Solution:
$(i)$. $a^2+b^2$
Putting $a=2$ and $b=-2$
$=2^2+(-2)^2$
$=4+4$
$=8$
$(ii)$. $a^2+ab+b^2$
Putting $a=2$ and $b=-2$
$=2^2+2(-2)+(-2)^2$
$=4-4+4$
$=4$
$(iii)$. $a^{2}-b^2$
Putting $a=2$ and $b=-2$
$=(2)^2-(-2)^2$
$=4-4$
$=0$
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