Add the following:$a-b+a b, b-c+b c, c-a+a c$
Given:
Given terms are $a-b+a b, b-c+b c, c-a+a c$.
To do:
We have to add the given terms.
Solution:
$(a-b+a b)+(b-c+b c)+(c-a+a c)=(a-a)+(-b+b)+(-c+c)+ab+bc+ac$
$=0+0+0+ab+bc+ca$
$=ab+bc+ca$
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