Add the following:$a-b+a b, b-c+b c, c-a+a c$


Given:

Given terms are $a-b+a b, b-c+b c, c-a+a c$.

To do:

We have to add the given terms.

Solution:

$(a-b+a b)+(b-c+b c)+(c-a+a c)=(a-a)+(-b+b)+(-c+c)+ab+bc+ac$

$=0+0+0+ab+bc+ca$

$=ab+bc+ca$ 

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Updated on: 10-Oct-2022

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