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Two numbers are in the ratio 5 : 6. If 8 is subtracted from each of the numbers, the ratio becomes 4 : 5. Find the numbers.
Given:
Two numbers are in the ratio $5: 6$. If 8 is subtracted from each of the numbers, the ratio becomes $4: 5$.
To do:
We have to find the numbers.
Solution:
Two numbers are in the ratio $ 5 : 6$.
Let the numbers be $5x$ and $6x$.
If 8 is subtracted from each number then it becomes $4 : 5$.
Therefore,
$(5x-8):(6x-8)=4:5$
$\frac{5x - 8}{6x - 8} = \frac{ 4}{ 5}$
On cross multiplication, we get,
$(5 x - 8)\times 5 = 4 \times (6 x -8)$
Multiplying the numbers inside the brackets,
$25 x - 40 = 24 x - 32$
$25 x - 24 x = -32 + 40$ (Keep variables on one side and numbers on the other side)
$x = 8$
This implies,
$5x=5(8)=40$ and
$6x=6(8)=48$
Therefore the numbers are 40 and 48 respectively.
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