The ages of Amar and Akbar are in the ratio 3:5 if after 10 years the ratio of their ages becomes 5:7 find ages
Given:
The ages of Amar and Akbar are in the ratio 3:5.
After 10 years, the ratio of their ages becomes 5:7.
To do:
We have to find their present ages.
Solution:
Let the age of the Amar be $3x$ years and the age of Akbar be $5x$.
This implies,
Age of Amar after 10 years $=3x+10$ years
Age of Akbar after 10 years $=5x+10$ years
According to the question,
$(3x+10):(5x+10)=5:7$
$\frac{3x+10}{5x+10}=\frac{5}{7}$
$7(3x+10)=5(5x+10)$
$21x+70=25x+50$
$25x-21x=70-50$
$4x=20$
$x=\frac{20}{4}$
$=5$
$\Rightarrow 3x=3(5)=15$ years
$\Rightarrow 5x=5(5)=25$ years
The present age of Amar is $15$ years and the present age of Akbar is $25$ years.
Related Articles
- The ages of Hari and Harry are in the ratio 5: 7 . Four years from now the ratio of their ages will be 3: 4. Find their present ages.
- The ages of Rahul and Haroon are in the ratio $5: 7$. Four years later the sum of their ages will be $56$ years. What are their present ages?
- The age of Anjali and Ankit are in the ratio of 5:7. Four years from now the ratio of their ages will be 3:4. Find their present ages.
- Raju is 19 years younger than his cousin. After 5 years, their ages will be in the ratio 2 : 3. Find their present ages.
- The present of Mohit and Mayank are in the ratio of $11:8$. After 8 years, their ages will be $5:4$. Find their present ages.
- The average age of a woman and her daughter is $25\ yr$. The ratio of their ages is $7: 3$, respectively. What will be the ratio of their ages after $9$ yr?
- The present ages of Sunita and Anita are in the ratio $3:5$. If Sunita had been $4$ years older and Anita $4$ years younger, the age of Sunita would have been $3$ times the age of Anita. Find their present ages.
- Shikha is 3 years younger than her brother Ravish. If the sum of their ages is 37 years, what are their present ages?
- The ratios of ages of A and B is $13:15$. After 9 years, the ratio will be $20:23$. What is the difference in years between ages?
- Is the following situation possible? If so, determine their present ages. The sum of the ages of two friends is 20 years. Four years ago, the product of their ages in years was 48.
- The sum of the ages of a man and his son is 45 years. Five years ago, the product of their ages was four times the man’s age at the time. Find their present ages.
- The ages of 5 teachers in my school are 32 years 28 years 24 years 38 years and 30 years. Find their average age.
- A girl is twice as old as her sister. Four years hence, the product of their ages (in years) will be160. Find their present ages.
- A father's age is three times the sum of the ages of his two children. After 5 years his age will be two times the sum of their ages. Find the present age of the father.
- Father’s age is three times the sum of ages of his two children. After 5 years his age will be twice the sum of ages of two children. Find the age of father.
Kickstart Your Career
Get certified by completing the course
Get Started