Triangle PQR is an isosceles triangle with PQ = PR. If angle R = 42 degree , find the measure of angle P

Given:

Triangle PQR is an isosceles triangle with $PQ = PR$.

$\angle R = 42^o$ 

To do:

We have to find the measure of angle P.

Solution:

Let the measure of angle P be $x$.

$PQ = PR$

This implies,

$\angle Q =\angle R =42^o$

We know that,

Sum of the angles in a triangle is $180^o$.

Therefore,

$angle P+angle Q+angle R = 180^o$

$x+42^o+42^o=180^o$

$x+84^o = 180^o$

$x=180^o-84^o$

$x=96^o$

Therefore, the measure of angle P is $96^o$.