The vertical angle of an isosceles triangle is 100 degree. Find its base angles.

Given:

The vertical angle of an isosceles triangle is 100 degrees.

To do:

We have to find the measure of the base angles of the triangle.

Solution:

Let the measure of each base angle be $x$.

We know that,

Sum of the angles in a triangle is $180^o$.

Therefore,

$x+x+100^o = 180^o$

$2x = 180^o-100^o$

$2x=80^o$

$x=\frac{80^o}{2}$

$x = 40^o$

Therefore, the measure of each of the base angles is $40^o$. 

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Updated on: 10-Oct-2022

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