Tick the correct answer:
Number of non overlapping Triangle we can make in a n-gon ( polygon having n
sides) , by joining the vertices is
a. n-1
b. n-2
c. n-3
d. n+2

Given: A $n-$gon $( polygon)$ with $n$ sides.

To do: To find the number of non overlapping triangle we can make in a $n-$gon$( polygon)$.

Solution:  

If we have a polygon with $n$ sides, then number of non overlapping triangles in a $n$-gon$( polygon)=n-2$.

Thus, option $( b)$ is correct.

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Updated on: 10-Oct-2022

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