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Solve: $\frac{n-1}{2}-\frac{n-2}{3}=\frac{n-4}{7}$.
Given: Expression: $\frac{n-1}{2}-\frac{n-2}{3}=\frac{n-4}{7}$.
To do: To find $n=?$
Solve:
$\frac{n-1}{2}-\frac{n-2}{3}=\frac{n-4}{7}$
$\Rightarrow \frac{3n-3-2n+4}{6}=\frac{n-4}{7}$
$\Rightarrow \frac{n+1}{6}=\frac{n-4}{7}$
$\Rightarrow 7n+7=6n-24$
$\Rightarrow 7n-6n=-24-7$
$\Rightarrow n=-31$
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