Solve: $\frac{n-1}{2}-\frac{n-2}{3}=\frac{n-4}{7}$.

Given: Expression: $\frac{n-1}{2}-\frac{n-2}{3}=\frac{n-4}{7}$.

To do: To find $n=?$

Solve:

$\frac{n-1}{2}-\frac{n-2}{3}=\frac{n-4}{7}$

$\Rightarrow \frac{3n-3-2n+4}{6}=\frac{n-4}{7}$

$\Rightarrow \frac{n+1}{6}=\frac{n-4}{7}$
 

$\Rightarrow 7n+7=6n-24$

$\Rightarrow 7n-6n=-24-7$

$\Rightarrow n=-31$

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Updated on: 10-Oct-2022

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