The students of a Vidyalaya were asked to participate s a competition for making and decorating pen holders in the shape of a cylinder with a base, using cardboard. Each pen holder was to be of radius $3\ cm$ and height $10.5\ cm$. The Vidyalaya was to supply the competitors with cardboard. If there were $35$ competitors, how much cardboard was required to be bought for the competition?
Given:
Each pen holder was to be of radius $3\ cm$ and height $10.5\ cm$.
There were $35$ competitors.
To do:
We have to find the cardboard that was required to be bought for the competition.
Solution:
Radius of the cylindrical pen holder $(r) = 3\ cm$
Height of the pen holder $(h) = 10.5\ cm$
Therefore,
The surface area of the pen holder $=2 \pi r h+\pi r^{2}$
$=\pi r(2 h+r)$
$=\frac{22}{7} \times 3(2 \times 10.5+3)$
$=\frac{66}{7}(21+3)$
$=\frac{66}{7} \times 24$
$=\frac{1584}{7} \mathrm{~cm}^{2}$
The number of pen holders made $=35$
This implies,
Total area of the cardboard required $=\frac{1584}{7} \times 35$
$=7920 \mathrm{~cm}^{2}$
Therefore,
The total area of the cardboard required is $7920 \mathrm{~cm}^{2}$.
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