The pillars of a temple are cylindrically shaped. If each pillar has a circular base of radius $20\ cm$ and height $10\ m$. How much concrete mixture would be required to build 14 such pillars?

 Given:

The pillars of a temple are cylindrically shaped.

Each pillar has a circular base of radius $20\ cm$ and height $10\ m$.

To do:

We have to find the concrete mixture required to build 14 pillars.

Solution:

Radius of each pillar $(r) = 20\ cm$

$=\frac{1}{5} \mathrm{~m}$

Height $(h)=10 \mathrm{~m}$

Therefore,

The volume of one pillar $=\pi r^{2} h$

$=\frac{22}{7} \times \frac{1}{5} \times \frac{1}{5} \times 10$

$=\frac{44}{35} \mathrm{~m}^{3}$

Volume of concrete in one pillar $=\frac{44}{35} \mathrm{~m}^{3}$

This implies,

Volume of concrete of 14 pillars $=\frac{44}{35} \times 14 \mathrm{~m}^{3}$

$=\frac{88}{5}$

$=17.6 \mathrm{~m}^{3}$

Tutorialspoint

Simply Easy Learning

Updated on: 10-Oct-2022

20 Views

Kickstart Your Career

Get certified by completing the course

Get Started