The present of Mohit and Mayank are in the ratio of $11:8$. After 8 years, their ages will be $5:4$. Find their present ages.

Given :

Present ages of Mohit and Mayank are in the ratio of $11:8$.

After 8 years, the ratio of their ages will be $5:4$.

To do :

We have to find their present ages.

Solution :

The present ages of Mohit and Mayank are in the ratio of $11:8$.

Let the Present age of Mohit be 11x and the age of Mayank be 8x.

After 8 years, the age of Mohit $=11x+8$

The age of Mayank $=8x+8$

After 8 years, the ratio of their ages will be $5:4$.

So, $\frac{11x+8}{8x+8}=\frac{5}{4}$

Cross multiply,

$4(11x+8) = 5(8x+8)$

$44x+32=40x+40$

$44x-40x = 40-32$

$4x=8$

$x = \frac{8}{4}$

$x=2$

The present ages of Mohit and Mayank are, $11x = 11(2)=22, 8x=8(2)=16$.

Therefore, the present ages of Mohit and Mayank are 22 and 16 respectively.

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Updated on: 10-Oct-2022

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