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Simplify each of the following:$ \frac{7.83 \times 7.83-1.17 \times 1.17}{6.66} $
Given:
\( \frac{7.83 \times 7.83-1.17 \times 1.17}{6.66} \)
To do:
We have to simplify the given expression.
Solution:
We know that,
$(a+b)^2=a^2+b^2+2ab$
$(a-b)^2=a^2+b^2-2ab$
$(a+b)(a-b)=a^2-b^2$
Therefore,
\( \frac{7.83 \times 7.83-1.17 \times 1.17}{6.66} \)
Let $a=7.83, b=1.17$
This implies,
$a-b=7.83-1.17=6.66$ and
$\frac{a \times a-b \times b}{a-b}=\frac{a^{2}-b^{2}}{a-b}$
$=\frac{(a+b)(a-b)}{a-b}$
$=a+b$
Therefore,
$\frac{7.83 \times 7.83-1.17 \times 1.17}{6.66}=7.83+1.17$
$=9.00$
$=9$
Hence, $\frac{7.83 \times 7.83-1.17 \times 1.17}{6.66}=9$.
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